Hi all, I am working on some EEG data and I would like to compute the power vs time. I know that i can perform an FFT to obtain the power, however, this would be for specific frequencies. I read that the power = magnitude square of the voltage. Is it valid then to compute the power at each time point by squaring the voltage magnitude and then plotting these against time to obtain the EEG power vs time plot? Thank you for your help in advance. cherrie

# Computing EEG power vs time

Started by ●October 2, 2007

Reply by ●October 2, 20072007-10-02

cherrie wrote:> Hi all, > > I am working on some EEG data and I would like to compute the power vs > time. I know that i can perform an FFT to obtain the power, however, this > would be for specific frequencies. I read that the power = magnitude > square of the voltage. Is it valid then to compute the power at each time > point by squaring the voltage magnitude and then plotting these against > time to obtain the EEG power vs time plot? > > Thank you for your help in advance. > > cherrie > >It is valid if you divide V^2 by the impedance. John

Reply by ●October 2, 20072007-10-02

John Sampson wrote:> cherrie wrote: >> Hi all, >> >> I am working on some EEG data and I would like to compute the power vs >> time. I know that i can perform an FFT to obtain the power, however, this >> would be for specific frequencies. I read that the power = magnitude >> square of the voltage. Is it valid then to compute the power at each time >> point by squaring the voltage magnitude and then plotting these against >> time to obtain the EEG power vs time plot? >> >> Thank you for your help in advance. >> >> cherrie >> >> > > It is valid if you divide V^2 by the impedance.Provided the impedance has no imaginary part. Jerry -- Engineering is the art of making what you want from things you can get. ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

Reply by ●October 2, 20072007-10-02

On Oct 2, 9:11 am, Jerry Avins <j...@ieee.org> wrote:> John Sampson wrote: > > cherrie wrote: > >> Hi all, > > >> I am working on some EEG data and I would like to compute the power vs > >> time. I know that i can perform an FFT to obtain the power, however, t=his> >> would be for specific frequencies. I read that the power =3D magnitude > >> square of the voltage. Is it valid then to compute the power at each t=ime> >> point by squaring the voltage magnitude and then plotting these against > >> time to obtain the EEG power vs time plot? > > >> Thank you for your help in advance. > > >> cherrie > > > It is valid if you divide V^2 by the impedance. > > Provided the impedance has no imaginary part. > > Jerry > -- > Engineering is the art of making what you want from things you can get. > =AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF==AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF= =AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF=AF Well if Z is complex then you can still talk about complex power, divide Vrms^2 by conj(Z). But I don't think the OP cares about that. John

Reply by ●October 2, 20072007-10-02

Reply by ●October 3, 20072007-10-03

Jerry Avins wrote:> John Sampson wrote: >> cherrie wrote: >>> Hi all, >>> >>> I am working on some EEG data and I would like to compute the power vs >>> time. I know that i can perform an FFT to obtain the power, however, >>> this >>> would be for specific frequencies. I read that the power = magnitude >>> square of the voltage. Is it valid then to compute the power at each >>> time >>> point by squaring the voltage magnitude and then plotting these against >>> time to obtain the EEG power vs time plot? >>> >>> Thank you for your help in advance. >>> >>> cherrie >>> >>> >> >> It is valid if you divide V^2 by the impedance. > > Provided the impedance has no imaginary part.cherriegeller@hotmail.co.uk wrote: > Hi, Thank you for your reply to my post \"compute EEG power vs time\". > You mentioned that its ok to do V^2 provided i divide by impedance. I > think this is from P=V^2/R ?? But how do i obtain R? This is EEG > recorded from the brain not from a circuitry?? Sorry i am really new > to this. Thanks Please correspond via the newsgroup unless the message is personal. Power is V^2/R where R is a real resistance and V is an RMS quantity. A decibel is (strictly) a measure of relative power, but it is often used to relate voltages *as if* there were real power involved. I imagine you aren't investigating how many watts the brain actually produces Isolated EEG signals wouldn't by themselves reveal that anyway. Use decibel measurements to provide relative fictitious power. For such an application, using magnitude or RMS merely changes an additive constant. Jerry -- Engineering is the art of making what you want from things you can get. ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

Reply by ●October 3, 20072007-10-03

>> Use decibel measurements to provide relative fictitious power. For suchan application, using magnitude or RMS merely changes an additive constant. Yes... or in other words: the reference to "relative fictious power" becomes a scaling factor c, as in c*V^2, hence: Simply use V^2. It might be R or it might be an empirically found (constant) fudge factor, as long as you don't require absolute powers. -mn

Reply by ●October 3, 20072007-10-03

>>> Use decibel measurements to provide relative fictitious power. Forsuch> >an application, using magnitude or RMS merely changes an additive >constant. > >Yes... or in other words: the reference to "relative fictious power" >becomes a scaling factor c, as in c*V^2, hence: Simply use V^2. > >It might be R or it might be an empirically found (constant) fudgefactor,>as long as you don't require absolute powers. > >-mn >Do you mean to just use V^2 to find the relative power and not dividing this by R?? Thanks,cherrie

Reply by ●October 3, 20072007-10-03

Reply by ●October 3, 20072007-10-03

On 2 Okt, 12:12, "cherrie" <cherriegel...@hotmail.co.uk> wrote:> Hi all, > > I am working on some EEG data and I would like to compute the power vs > time. I know that i can perform an FFT to obtain the power, however, this > would be for specific frequencies. I read that the power = magnitude > square of the voltage. Is it valid then to compute the power at each time > point by squaring the voltage magnitude and then plotting these against > time to obtain the EEG power vs time plot?That's generally the case, yes. I don't know if this is valid for EEG signals, but for the types of signals I usually work with I prefer to use an envelope detector before squaring the amplitudes. The power curve becomes somewhat smoother that way. Rune