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Fraunhofer image formation

Started by alex...@kcl.ac.uk August 28, 2006
Hi there

Thanks to those people who replied to my phase wrapping problem, I think I understand the situation better now. I have (possibly obvious) question with regards to Fraunhofer diffraction, please help!

Basically I'm confused as to the difference between a point spread function (obtained using an FFT) and the images that you see on photographic film in standard optics textbooks, e.g. for the Fraunhofer pattern of a square aperture (i.e. Hecht, pg. 466). To get the Fraunhofer you bascially take the Fourier transform, yet it is only when you plot it over a log scale that the image becomes like those seen on photographic film. (Sorry I know this is more of an optics question that a matlab question). A friend of mine suggested that because the FT performs an exponential, to get a linear image as you would see in reality you must therefore take the natural logarithm. Is this correct? I'd appreciate any advice here.

Cheers,
Alex