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`(11!)/(4!4!2!)``(11!)/(4!4!)``(11!)/(4!2!)`none of these

Answer :

ASolution :

There are 11 letters in the given word, of which 4 are S's 4 are 1's and 2 are P's. So, total number of words is the number of arrangements of 11 things, of which 4 are similar of one kind, 4 are similar of second kind and 2 are similar of third kind i.e., `(11!)/(4!4!2!)` <br> Hence, the total number of words `(11!)/(4!4!2!)`.**What is factorial Zero Factorial examples**

**(a)Compute (i) `(20!)/(18!)` (ii) `(10!)/(6!.4!)` (b)find n if `(n+2)! =2550*n!`**

**fundamental principle of multiplication**

**fundamental principle of addition**

**Difference and application of fundamental principals**

**There are 3 condidates for a Classical; 5 for a Mathematical and 4 for a Natural science scholarship.(i)In how many ways can these scholarship be awarded ? (ii) In how many ways one of these scholarships be awarded?**

**What is permutation ?**

**Notation + theorem :- Let r and n be the positive integers such that `1lerlen`. Then no. of all permutations of n distinct things taken r at a time is given by `(n)(n-1)(n-2).....(n-(r-1))`**

**Prove that `P(n,r)=nP_r=(n!)/((n-r)!`**

**The no. of all permutation of n distinct things taken all at a time is `n!`**