ASM code: meaning of instructions

Hi all,
I am new to c55x programming, I am tring to understand one ASM code, can anyone explain meaning of instructions in brief.

MOV XAR1,dbl(@#02h)
MOV XAR0,dbl(@#00h)
MOV dbl(@#00h),XAR
MOV dbl(@#02h),XAR3

I am confused with term like dbl(@#02h). Start a New Thread

Rahul-

> I am new to c55x programming, I am tring to understand
> one ASM code, can anyone explain meaning of instructions
> in brief.
>
> MOV XAR1,dbl(@#02h)
> MOV XAR0,dbl(@#00h)
> MOV dbl(@#00h),XAR
> MOV dbl(@#02h),XAR3
>
> I am confused with term like dbl(@#02h).

'dbl' means to move two (2) 16-bit words, or 32 bits. Note that high word is stored first in memory, followed by low
word.

-Jeff Start a New Thread

Hi,
In the code provided by you, as the source or destination register(XAR) is
of 24 bit, it will load or store least significant 24 bits.
the term "dbl(@#02h)" implies, the base address is stored in SP or DP
depending on the CPL bit in status registers, and from that #02 is the
offset.

Regards,
Chandrakala.

On Sat, Aug 23, 2008 at 7:08 PM, wrote:

> Hi all,
> I am new to c55x programming, I am tring to understand one ASM code, can
> anyone explain meaning of instructions in brief.
>
> MOV XAR1,dbl(@#02h)
> MOV XAR0,dbl(@#00h)
> MOV dbl(@#00h),XAR
> MOV dbl(@#02h),XAR3
>
> I am confused with term like dbl(@#02h).
>
> Start a New Thread