Hi guys, I am building a synchroniser for OFDM. I read in a paper that the FFT window can start anywhere in the Cyclic prefix, & that this only results in Phase rotation at the output of FFT. 1st, is this right? 2nd, how do we fix these phase rotation? In some papers I read, I think I am supposed to calculate the angle of the 1st symbol, & rotate all the other symbols by same degree. But this isnt working? What am I doing wrong? Is this the correct way to fix phase rotation?
Phase rotation for FFT in OFDM
Started by ●December 1, 2006
Reply by ●December 1, 20062006-12-01
gadha wrote:> Hi guys, > > I am building a synchroniser for OFDM. I read in a paper that the FFT > window can start anywhere in the Cyclic prefix, & that this only results > in Phase rotation at the output of FFT. 1st, is this right? >correct, see the shifting theorem> 2nd, how do we fix these phase rotation? In some papers I read, I think I > am supposed to calculate the angle of the 1st symbol, & rotate all the > other symbols by same degree. But this isnt working? > > What am I doing wrong? Is this the correct way to fix phase rotation?Obviously not. Xe(k) = X(k) * exp(j*2*pi*tau*k/N), where tau is your timing error, N is the fft size (k=0...N-1), Xe(k) is the FFT of the timing error samples and X(k) is the desired FFT samples. col