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Hi, in the implementation of the filter H(z) = (sigma)h(n)z^-n; is it possible to directly use this expression and obtain the frequency response in z domain. thanks in advance. sree. |
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usage of z directly
Started by ●November 22, 2002
Reply by ●November 22, 20022002-11-22
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Sure, but the "frequency response" of a filter is the z-transform evaluated along the unit circle, where z = exp(j*w), w from -pi to pi. So the frequency response is H(w) = summation over n of h(n)*exp(j*w*n). This is all you need to evaluate the frequency response of your filter. Sincerely, Glen Ragan |
