Mass Reflectance from Either StringLet's first consider how the mass looks from the viewpoint of string 1, assuming string 2 is at rest. In this situation (no incoming wave from string 2), string 2 will appear to string 1 as a simple resistor (or dashpot) of Ohms in series with the mass impedance . (This observation will be used as the basis of a rapid solution method in §9.3.1 below.)
When a wave from string 1 hits the mass, it will cause the mass to move. This motion carries both string endpoints along with it. Therefore, both the reflected and transmitted waves include this mass motion. We can say that we see a ``dispersive transmitted wave'' on string 2, and a dispersive reflection back onto string 1. Our object in this section is to calculate the transmission and reflection filters corresponding to these transmitted and reflected waves. By physical symmetry the velocity reflection and transmission will be the same from string 1 as it is from string 2. We can say the same about force waves, but we will be more careful because the sign of the transverse force flips when the direction of travel is reversed.10.12Thus, we expect a scattering junction of the form shown in Fig.9.17 (recall the discussion of physically interacting waveguide inputs in §2.4.3). This much invokes the superposition principle (for simultaneous reflection and transmission), and imposes the expected symmetry: equal reflection filters and equal transmission filters (for either force or velocity waves).
The traveling-wave decompositions can be written out as
where a ``+'' superscript means ``right-going'' and a ``-'' superscript means ``left-going'' on either string.10.13 Let's define the mass position to be zero, so that Eq.(9.14) with the substitutions Eq.(9.15) becomes
From this, the reflected velocity is immediate:
Simplified Impedance Analysis
Mass Termination Model