Forums

transmit information

Started by omg January 12, 2006
base on the shannon capacity limit,dicuss the possibility of transmitting
information when siganl is lower than the noise?

some ways of trasmitting would be be spreading the specturm,using reed
coding method.

what are some other ways to transmit information when signal is lower
than
the noise


You can average out the noise to reveal a signal. Your averaging window size 
has to be less that or equal to the bit rate or you will start to average 
out the information.

Thomas

"omg" <jimmybai123@yahoo.com> wrote in message 
news:csmdnczuxoEBb1veRVn-tQ@giganews.com...
> > base on the shannon capacity limit,dicuss the possibility of transmitting > information when siganl is lower than the noise? > > some ways of trasmitting would be be spreading the specturm,using reed > coding method. > > what are some other ways to transmit information when signal is lower > than > the noise > >
omg wrote:
> base on the shannon capacity limit,dicuss the possibility of transmitting > information when siganl is lower than the noise? > > some ways of trasmitting would be be spreading the specturm,using reed > coding method. > > what are some other ways to transmit information when signal is lower > than the noise
What, again? Does your prof keep asking the same question or are you stuck in a time loop? Jerry -- Engineering is the art of making what you want from things you can get. &#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;
"Jerry Avins" <jya@ieee.org> wrote in message 
news:cPmdnfxwO94DRVrenZ2dnUVZ_tydnZ2d@rcn.net...
> omg wrote: >> base on the shannon capacity limit,dicuss the possibility of transmitting >> information when siganl is lower than the noise? >> >> some ways of trasmitting would be be spreading the specturm,using reed >> coding method. >> >> what are some other ways to transmit information when signal is lower >> than the noise > > What, again? Does your prof keep asking the same question or are you stuck > in a time loop? > > Jerry > -- > Engineering is the art of making what you want from things you can get. > &#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;
I should have said...The frequency in which you asked this question can be filtered by averaging the background noise of unique questions. You should see some spectral gain at around 1.751 E-6 Hz. Thomas
the magic number is  -1.6 dB

Mark

By the way, why are there also so many answers although they are not
real answers to the requested question? It is very interesting to me
that somebody not just ignores it but posts something to the question.
Is it because we already become familiar with that question as we are
familiar with Gooooooogle.

- James Gold

James G. wrote:
> By the way, why are there also so many answers although they are not > real answers to the requested question? It is very interesting to me > that somebody not just ignores it but posts something to the question. > Is it because we already become familiar with that question as we are > familiar with Gooooooogle.
Frustration at the same question being asked repeatedly by someone who seemingly doesn't know what it means. Jerry -- Engineering is the art of making what you want from things you can get. &#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;&#2013266095;